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Formulas for KE and stored energy in a bow

Started by Jeff Cooper, February 07, 2007, 01:15:00 AM

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Jeff Cooper

Could someone please give me the formulas for figuring out KE in an arrow (I think it is mass X velocity squared divided by 450,240) And I really don't remember the formula for figuring out stored energy underneath the line on a force-draw-curve. Any help is greatly appreciated. Jeff Cooper

sunny hill archer

Mass (in grains) multiplied by velocity (in feet per second) squared divided by 450240 equals KE in ft/lbs of force.
The old order is passing. Swiftly receding into memory are the days of strong, earnest men who followed an atavistic yearning to pit their skills against wild animals.

Billy Ellis

Michael Harnage

Area under the force draw curve is just area. Area is length times width. Usually it's close enough to take 1/2 of the peak weight and multiply by the distance drawn. Then factor in the efficiency and you should get the same KE that arrow shows across the chrono.

Jeff Cooper

Thanks guys.  What I am looking for is the formula to convert the area underneath the force draw curve into a useable number for ft-lbs of stored energy (SE), so I can compare my arrow's KE to my bow's SE in order to measure the bow's efficiency using different weight arrows...trust me, I do not get this technical for my everyday shooting...I just need to get through this science project. Again thanks to all who have or may respond...now it is back to the homework!

AkDan

man that hurts, you didnt believe me ugg ON THE ke formula!

If ya need help let me know, other then sledding tomorrow I'm wide open!!!!

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